LeetCode Solutions: https://www.youtube.com/playlist?list=PL1w8k37X_6L86f3PUUVFoGYXvZiZHde1SJune LeetCoding Challenge: ... ... <看更多>
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LeetCode Solutions: https://www.youtube.com/playlist?list=PL1w8k37X_6L86f3PUUVFoGYXvZiZHde1SJune LeetCoding Challenge: ... ... <看更多>
@lc app=leetcode.cn id=70 lang=c. *. * [70] 爬楼梯. *. * https://leetcode-cn.com/problems/climbing-stairs/description/. *. * algorithms. * Easy (43.66%). ... <看更多>
if n==1 the code should return dp[n-1] i.e. dp[0] , but that does not seem to be the case. Yes. But when n == 1 , you call dp[1] = 2;. ... <看更多>
Climbing Stairs. Description. You are climbing a stair case. ... 2 var a = 1 var b = 2 var c: Int for (i in 2 until n) { c = b b += a a = c } return b } }. ... <看更多>
Here is pseudocode for solving this, using a recursive procedure: All-Solutions(n):. If n=0, return the solution (empty sequence). ... <看更多>