nonsingular matrix 在 Matrix equation Ax=b is A nonsingular when $b \in \mathbb{R}^n 的評價 To show that if Ax=b has solution for all b, then A must be non-singular: The equations Ax=ei. has solution xi. Then A(x1,x2,⋯,xn)=(e1,e2,⋯,en)=I. ... <看更多>
nonsingular matrix 在 Matlab - generate random nonsingular triangular matrix 的評價 your answer is correct: A=tril(rand(n)). you can check that this matrix is not singular using rcond(A)>eps. or min(svd(A))>eps. ... <看更多>
